Question:
An alternating current, 𝑖 amperes, is given by 𝑖 = 10sin2𝜋𝑓𝑡, where 𝑓 is the frequency in hertz and 𝑡 the time in seconds. Determine the rate of change of current when 𝑡 = 20𝑚𝑠, given that 𝑓 = 150𝐻𝑧.
Answer:
Firstly add the constant for frequency (𝑓 = 150Hz) into the equation given for current:
![](https://static.wixstatic.com/media/20c892_0ffa0114e00e44829d3c8b8af1e8a0c9~mv2.png/v1/fill/w_81,h_8,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_0ffa0114e00e44829d3c8b8af1e8a0c9~mv2.png)
Differentiate and input the variable 𝑡, (remember 20ms = 0.02s).
![](https://static.wixstatic.com/media/20c892_4053c25581f6435085b19542c32b17c3~mv2.png/v1/fill/w_80,h_22,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_4053c25581f6435085b19542c32b17c3~mv2.png)
Question:
The luminous intensity, 𝐼 candelas, of a lamp is given by:
![](https://static.wixstatic.com/media/20c892_55889cb6026b4be0966fb732d8327e65~mv2.png/v1/fill/w_80,h_4,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_55889cb6026b4be0966fb732d8327e65~mv2.png)
where 𝑉 is the voltage. Find:
a) the rate of change of luminous intensity with voltage when 𝑉 = 200𝑣𝑜𝑙𝑡𝑠
b) the voltage at which the light is increasing at a rate of 0.3 candelas per volt.
Answer:
a)
![](https://static.wixstatic.com/media/20c892_15d52e6fb977493a917b38627b94e95c~mv2.png/v1/fill/w_78,h_26,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_15d52e6fb977493a917b38627b94e95c~mv2.png)
b)
![](https://static.wixstatic.com/media/20c892_9038a2e501d5441b9b32033de78c3dc1~mv2.png/v1/fill/w_82,h_18,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_9038a2e501d5441b9b32033de78c3dc1~mv2.png)
Question:
The voltage across the plates of a capacitor at any time 𝑡 seconds is given by
![](https://static.wixstatic.com/media/20c892_612a774db57f48188ef0c8caec1aab80~mv2.png/v1/fill/w_80,h_6,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_612a774db57f48188ef0c8caec1aab80~mv2.png)
where 𝑉,𝐶 and 𝑅 are constants. Given 𝑉 = 300volts, 𝐶 = 0.12 × 10−6F and 𝑅 = 4 × 106Ω, find:
a) the initial rate of change of voltage
b) the rate of change of voltage after 0.5 s.
Answer:
a)
![](https://static.wixstatic.com/media/20c892_a959781131734c0ca805af5d09a9172b~mv2.png/v1/fill/w_79,h_45,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_a959781131734c0ca805af5d09a9172b~mv2.png)
b)
![](https://static.wixstatic.com/media/20c892_d1b614e339a74df899740204eb699a41~mv2.png/v1/fill/w_79,h_15,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_d1b614e339a74df899740204eb699a41~mv2.png)
Question:
The pressure 𝑝 of the atmosphere at height ℎ above ground level is given by:
![](https://static.wixstatic.com/media/20c892_141543973d8044a0b65a8f7698e3b227~mv2.png/v1/fill/w_79,h_6,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_141543973d8044a0b65a8f7698e3b227~mv2.png)
where 𝑝0 is the pressure at ground level and 𝑐 is a constant. Determine the rate of change of pressure with height when 𝑝0 = 1.013 × 105 pascals and 𝑐 = 6.05 × 104 at 1450metres.
Answer:
a)
![](https://static.wixstatic.com/media/20c892_24c9b6b4f3db42fdafd60dabaace334e~mv2.png/v1/fill/w_81,h_24,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_24c9b6b4f3db42fdafd60dabaace334e~mv2.png)
Input the 1450m height variable:
![](https://static.wixstatic.com/media/20c892_f2ccc2263f934e64b4efcfedf36ac5df~mv2.png/v1/fill/w_79,h_15,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_f2ccc2263f934e64b4efcfedf36ac5df~mv2.png)
Question:
The volume, 𝑣 m3, of water in a reservoir varies with time 𝑡, in minutes. When a valve is opened the relationship between 𝑣 and 𝑡 is given by:
![](https://static.wixstatic.com/media/20c892_9d3e1a155ab84208a394f7476f6d3867~mv2.png/v1/fill/w_82,h_4,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_9d3e1a155ab84208a394f7476f6d3867~mv2.png)
Calculate the rate of change of water volume at the time when 𝑡 = 3 minutes.
Answer:
![](https://static.wixstatic.com/media/20c892_a0cfb437a8974947a1d4ddeac167274f~mv2.png/v1/fill/w_82,h_22,al_c,q_85,usm_0.66_1.00_0.01,blur_2,enc_auto/20c892_a0cfb437a8974947a1d4ddeac167274f~mv2.png)